multisim 7 segment display birthday nand

With too much power, the LEDs would burst.74LS93 or SN74LS93 is a 4-bit binary counter. The resistor in front of the display makes sure the display does not get to much power and breaks. Our constraint required us to use a common cathode display. Common Anode needs an input of 0 to power a segment on, and it is connected to power. Now a common cathode needs an input of 1 to a segment to turn it on, and it is grounded. With a combination of segments, it can display numbers and letters. When given the correct input, it powers on. It's important to have less chips, because less chips mean you save more money.Ī seven segment display has 7 LEDs inside of it, each for one of the segments. It could have easily just used AOI, and reduced the number of chips needed by 1. As I write this, I realize that my NAND segment actually created more problems for me. A circuit with 1 AND gate and 1 OR gate would need 2 different chips, but with NOR gates, it would only need 1 chip. The reason we use NOR/NAND is because it can reduce how many chips we would need to use. None of my other segments would need AND gates, so all of them could have easily been made with NOR gates. For segment B, there was really no reason for choosing NOR. For segment E, I used NAND gates because it was my only segment that would require AND gates. To create this circuit, you need 1 OR Chip, 2 NAND Chips, 1 NOR Chip, and 1 Invertor Chip. On MultiSim, we needed resistors in our circuit, but in the breadboards had built in resistors, so we don't have resistors plugged in. So the top is segment B, and the bottom is segment G. The circuits are in alphabetical order from top to bottom (excluding A/D). My segments A/D are plugged directly into a power source near the cathode. My circuit is in bus form in order to make the wiring look neater. Each segment, A-G, gets there own expression, which is why there is so many. Karnough mapping puts the expression in SOP, and it is considerably faster than Boolean, which is why people use it instead of Boolean. So a straight row of 4 in the first column is only Z', because the X/Y changes so it doesn't matter what they are. Using the terms on the left, you can find out the minterm of each group. If you grouped the top half, then the bottom, you would have an unnecessarily larger expression. For A, you can group all of them together with the X's included. The X's can be ones or zeros, so you want to use those X's to create the largest groups possible. When Karnough mapping, the goal is to create the biggest groups possible and get all of the ones included in the expression. A circuit with 2 inputs would only have a 2x2 square.

So a circuit with 3 inputs, like mine, has a square this size. The size of the Karnough square is determined by the size of the circuit. Karnough mapping is a technique used in order to simplify a logic expression.

Multisim 7 segment display birthday nand